Wednesday, November 7, 2012
IsoMorphic Binary Trees
Two trees can be called isomorphic if they have similar structure and the only difference amongst them can be is, that their child nodes may or may not be swapped..
For example
The trees in the above picture are called Isomorphic Trees.The following code checks whether two trees are Isomorphic or not.
Code:(Written in C)
int is_isomorphic(struct node *t1,struct node *t2)
{
if(t1==NULL && t2==NULL)
return 1;
if(t1==NULL || t2==NULL || t1->data!=t2->data)
return 0;
return (is_isomorphic(t1->left,t2->left)&&is_isomorphic(t1->right,t2->right) || is_isomorphic(t1->left,t2->right)&&is_isomorphic(t1->right,t2->left) );
}
Please let me know if u have any questions
Thursday, October 25, 2012
Program to find Lowest Common Ancestor of two nodes
To find a Lowest or Least Common Ancestor of binary tree we need to pass three arguments .Those are root node of binary tree and the node details to find common ancestor (here node data's are used) . The following code recursively searches for the nodes that we need to find. When it finds the node it returns the node. If both the left and right side of the node returns the node this is it(the node is called as common ancestor) .Else the process will continue until it finds the common ancestor.
For an Example
In the following tree
10
/ \
5 12
/ \
3 8
/
7
for nodes 7 and 3 LCA(Lowest Common Ancestor) is 5.
Code (Written in C):
struct node* lowestCommonAncestor(struct node* node, int n1,int n2)
{
if(node==NULL)
return NULL;
if(node->data==n1 || node->data ==n2)
return node;
else
{
struct node* left,right;
left=lowestCommonAncestor(node->left,n1,n2);
right=lowestCommonAncestor(node->right,n1,n2);
if(left&&right)
return node;
else
return left==NULL?right:left;
}
}
For an Example
In the following tree
10
/ \
5 12
/ \
3 8
/
7
for nodes 7 and 3 LCA(Lowest Common Ancestor) is 5.
Code (Written in C):
struct node* lowestCommonAncestor(struct node* node, int n1,int n2)
{
if(node==NULL)
return NULL;
if(node->data==n1 || node->data ==n2)
return node;
else
{
struct node* left,right;
left=lowestCommonAncestor(node->left,n1,n2);
right=lowestCommonAncestor(node->right,n1,n2);
if(left&&right)
return node;
else
return left==NULL?right:left;
}
}
Tuesday, July 10, 2012
Efficient java program to find GCD of given two numbers
The following java code finds the biggest common factor(GCD) for two numbers easily. Otherwise we need to check it from smallest number.Lets assume that the smallest number is n. So we need to check it from n,n-1....1 to find the common factor.But here out of two inputs set the biggest one to b. Then find the common factor using the % operator and keep changing the values of a and b until you find the common factor.
Code : (in JAVA)
Sample input and output
1.Input
8 5
Output
1
2.Input
26 4
Output
2
Please let me know if you have any questions .
Code : (in JAVA)
Sample input and output
1.Input
8 5
Output
1
2.Input
26 4
Output
2
Please let me know if you have any questions .
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