C Program to Rotate 2D array by 90 degrees

This concept is used in rotating images .Rotating array by 180 degree is very easy .
For an example if the array is (let's assume 5x5 array)
1   2   3   4   5
6   7   8   9  10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25

and if we rotate it by 180 degrees it will look like
21 22 23 24 25
16 17 18 19 20
11 12 13 14 15
6   7   8   9  10
1   2   3   4   5

we can acheieve it by swapping first row and last row , second row and fourth row.
But to achieve 90 degree rotation the steps are
 i) rotate array by 180 degrees first .
 ii)for every element(i,j) in 2D matrix , if i < j swap (i,j) and (j,i) .
So the output will be 90 degrees rotated
 21 16 11 6   1
 22 17 12 7   2
 23 18 13 8   3
 24 19 14 9   4
 25 20 15 10 5

 Note :Here we are doing it in place.This will work only if m and n are same. otherwise we need to create a new array of size nxm .

 Code : (in C)

  void rotate90Degrees(int **array,int m ,int n)  // mxn matrix
 {
     int i,j,rows=m-1,temp;
 
     //rotate array by 180 degrees
     for(i=0;i<=rows/2;i++)
     {
if(rows<=i)
break;
for(j=0;j < n;j++)
{
temp=array[i][j];
array[i][j]=array[rows][j];
array[rows][j]=temp;
}
rows--;
       }
 
      //swap elements to rotate array by 90 degrees
      for(i=0;i < m;i++)
     {
for(j=0;j < n;j++)
{
if(i < j)
{
temp=array[i][j];
array[i][j]=array[j][i];
array[j][i]=temp;
}
               }
       }
 }

Please let me know if there is any bug in the above code and your suggestions are always welcome .